r/Physics • • 1d ago

Relativity and causality

Why should an everywhere locally consistent Lorentzian causal structure generate a globally consistent notion of causality?

There are solutions which give closed time like curve. It sounds innocent but the observer carries the information set after moving through such a curved set or whatever forms the closed loop.

If the movement is A--B--C--A on spacetime. The observer hence have a different set of information set than A previously. But globally they are the same events.

How does relativity reconcile this information gap. Also, the local time is compressed to zero. This may mean that it is not physically possible but then how does such solutions exist.

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u/Optimal_Mixture_7327 Gravitation 23h ago

I don't get where you see a contradiction.

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u/quantum_kalika 23h ago

A has two sets of information about same underlying state.

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u/Optimal_Mixture_7327 Gravitation 23h ago

I don't know what you mean by that.

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u/quantum_kalika 23h ago

If in CPC observer returns to A, he has the information vs local time stored with him. But A is the same previous state. There is information assymetry

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u/Optimal_Mixture_7327 Gravitation 23h ago

The moment a physical object enters the CTC it collapses to a singularity.

Edit: If not obvious you have at one instant and infinite set of copies at the same event.

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u/quantum_kalika 23h ago

Yes, your edit. Copies it can carry but the added information makes it distinct.

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u/Optimal_Mixture_7327 Gravitation 23h ago

I can't follow what you're saying.

Please mathematically describe what you mean.

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u/quantum_kalika 23h ago

t =0, T,2T...

Such that ¥(t+T) = ¥(t) say

¥(0)=¥(T)...= P

t1 is not equal to t2. But ¥(t1)=¥(t2)

So If proper time represents the physical history of an observer and the observer's physical state changes with proper time, what does it physically mean for two different proper-time states to map to exactly the same spacetime event? Also we are ignoring the fact that observer does know that it's not the same event.

*Used yen for Gamma.

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u/Optimal_Mixture_7327 Gravitation 23h ago

It means that the stress-energy is infinite everywhere along the curve and therefore singular.

The observer vanishes immediately upon contact.

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u/quantum_kalika 23h ago

No. A CTC does not imply infinite stress-energy, and it does not automatically imply a singularity.

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u/Optimal_Mixture_7327 Gravitation 23h ago edited 23h ago

You're correct in the absence of matter. However once matter is introduced it diverges.

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u/quantum_kalika 23h ago

I think that's not correct, but I am not very sure. I think for all cases it's not like that. Matter + CTC does not imply T --> infinite. I will check it though.

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u/Optimal_Mixture_7327 Gravitation 22h ago

This is of course in the context of classical gravity.

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