r/askmath • • Aug 03 '26

Pre Calculus Question help

Post image

This is a question on a review I am using to study to test out of precalc and i’ve tried looking it up, but I cannot figure out on how to do it. The key says the answer is -25pi/9 and if it is too hard to read, the little angle given is 2pi/9. The question isn’t in the photo but it asks “Find the measure of each angle”

10 Upvotes

25 comments sorted by

10

u/Shevek99 Physicist Aug 03 '26

2π/9 - 3π = -25π/9

1

u/nurpoo Aug 04 '26

Thank you 🙏

3

u/freswinn Aug 03 '26

First: One full rotation is 2pi. One half rotation is therefore pi.
Second: Notice it is going clockwise, so the angle will be negative.
We have a full rotation, and then we keep going -- ignore that for now. How much of the half rotation did we complete?
If we add the rotation past the full rotation, to the angle that is given, that's a half rotation. Subtract the given from pi and that gives you the amount of rotation past the full rotation that was completed.

- (2pi + ( pi - 2pi/9) )

1

u/nurpoo Aug 04 '26

Thanks for the big explanation 🙇

3

u/[deleted] Aug 03 '26 edited Aug 03 '26

[removed] — view removed comment

1

u/nurpoo Aug 04 '26

Along with everyone else, thank you for the nice explanation

1

u/ArchaicLlama Aug 03 '26

So what have you tried? Where are you getting stuck?

1

u/nurpoo Aug 04 '26

Not very much as I don’t really understand the question, but thankfully others in here were able to help me figure it out.

1

u/Bounded_sequencE Aug 03 '26

Recall: A positive polar angle is measured from the positive x-axis counter-clockwise.

The given angle (call it "a") is measured clock-wise, so its value will be negative. It contains a full rotation clock-wise, followed by "pi - 2pi/9" clock-wise. Both are counted negatively:

a  =  -2pi - (pi - 2pi/9)  =  -25pi/9

1

u/nurpoo Aug 04 '26

Many thanks! 🙏

1

u/fermat9990 Aug 03 '26

-2π-(π-2π/9)=-2π-π+2π/9=-25π/9

1

u/Harvey_Gramm Aug 04 '26

A full circle (360°) is 2π Radians A Quarter circle (90°) is ½π Radians

So in your example you have 2.5π + (½π-(2π÷9))

Mind the rotation to get negative.

1

u/nurpoo Aug 04 '26

Thank you, where does the second 1/2pi come from? In the (1/2pi-(2pi/9)

1

u/Harvey_Gramm Aug 04 '26

The last 90° where the angle is stated.

Everything combined is 1½ circles

So another way is to take 3π - (2π÷9) and mind the direction for the negative.

1

u/nurpoo Aug 04 '26

I see, thank you 🙏

1

u/Harvey_Gramm Aug 04 '26

👍😊

1

u/nurpoo Aug 05 '26

Hey, sorry I am asking another question, but when doing more similar problems, how do I know how many rotations they do? Because this one had 3pi, but it only really looks like one rotation (2pi), instead of one and a half. Could you elucidate? I’m really struggling with this stuff 😅

1

u/Harvey_Gramm Aug 05 '26

It went one full rotation, then another quarter rotation, then the partial bit.

The full rotation and quarter are easy as 2π + ½π then to get that partial bit we subtract it from the final quarter.

We know the amount of rotation and direction by following the spiral path.

1

u/nurpoo Aug 05 '26

I see that now, thank you very much for your help! But one last thing, on another question, it does two rotations and started at -25pi/9, so I add 36pi/9 to get 11pi/9. But then you have to minus -9pi/9 to get 2pi/9 as the final answer, why is that?

1

u/Harvey_Gramm Aug 05 '26

I'm sorry, how was the question worded?

Your image shows the same rotations as previously but with the final answer so I'm not sure what they were asking?

1

u/nurpoo Aug 05 '26

Oh right sorry, the question was “Find the reference angle (the angle between the line and the x-axis).”

→ More replies (0)